Titrate 10mL of the unknown to determine the acid concentration and
5 mL of the unknown for the concentration of the salt.
Do not forget that in the second titration the phosphoric acid in
the original sample has been titrated twice, once to
H2PO4- and again to
H2PO42-. Suppose that the unknown
is y molar in phosphoric acid and z molar in sodium dihydrogen phosphate.
The first titration determines y, since the end-point corresponds to
completion of the reaction:
H3PO4 + NaOH --> NaH2PO4 + H2O
The second titration again starts with fresh unknown, so the first portion
of NaOH added changes the H3PO4 to
NaH2PO4. After this portion has been added, the solution
is y + z molar in NaH2PO4. Further addition of base will
neutralize not only the z molar NaH2PO4 originally present
in the unknown but also the y molar salt formed from the y molar
H3PO4 originally present, forming Na2HPO4
from both when the end-point is reached. The chemical reactions for the second
titration are:
H3PO4 (y molar) + 2 NaOH --> Na2HPO4 + 2 H2O
Na2HPO4 (z molar) + NaOH --> Na2HPO4 + H2O
Thus, for the second end point: MBase x VBase = VSample x 2y + VSample x z